Question

a force 2i +j has moved its point of application from (2,3) to (6,5). what is the work done

Answer 1

Answer:

W=∫dW=∫F.dl

Explanation:

Answer 2

Concept:

• Work done
• Work as a function of displacement
• Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement.

Given:

• Force F = 2 i + j
• Initial point (2,3) S1 = 2 i + 3 j
• Final point (6,5) S2 = 6 i + 5 j

Find:

• The work done

Solution:

The displacement vector = S2 -S1

Displacement = 6 i + 5 j - (2 i + 3 j)

Displacement = 6i - 2i + 5j - 3j

Displacement = 4i + 2j

We know that work done is the scalar product of the force and the displacement.

W = F.S

W = (2 i + j). (4i + 2j)

W = 2(4) + 1(2)

W = 8 + 2

W = 10 J

The work done is 10 J.

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