Physics, asked by Aaravkumar152, 1 year ago

A force 30 n inclined at an angle theta to the horizontal.if its vertical component is 18 n.find the horizontal component and the value of theta?

Answers

Answered by shrikant7
9
30sinthetha = 18

sinthetha = 18/30

= 3/5


Ф = 37°

horizontal component = 30cosФ = 30cos37

= 30 x 4/5

= 24 N
Answered by vrajpatel30503
2

Answer:

Explanation:

30sinthetha = 18

sinthetha = 18/30

= 3/5

Ф = 37°

horizontal component = 30cosФ = 30cos37

= 30 x 4/5

= 24 N

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