A force 30 n inclined at an angle theta to the horizontal.if its vertical component is 18 n.find the horizontal component and the value of theta?
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Answered by
9
30sinthetha = 18
sinthetha = 18/30
= 3/5
Ф = 37°
horizontal component = 30cosФ = 30cos37
= 30 x 4/5
= 24 N
sinthetha = 18/30
= 3/5
Ф = 37°
horizontal component = 30cosФ = 30cos37
= 30 x 4/5
= 24 N
Answered by
2
Answer:
Explanation:
30sinthetha = 18
sinthetha = 18/30
= 3/5
Ф = 37°
horizontal component = 30cosФ = 30cos37
= 30 x 4/5
= 24 N
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