A force (3i + 4j) N acts on a body and displaced it by (-3j + 4i) metre. The work done
by the force is
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Answer:
12√2
Explanation:
Work=F•d=Fdcos¢
=(3i+4j)×(4i-3j)
=(12i-12j)
Magnitude=√(12i)^2 + (12j)^2
=√2×12×12
=12√2 J
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