Physics, asked by sharmapragati1406, 8 months ago

A force (3i + 4j) N acts on a body and displaced it by (-3j + 4i) metre. The work done
by the force is

Answers

Answered by jai344dk

1

Answer:

12√2

Explanation:

Work=F•d=Fdcos¢

=(3i+4j)×(4i-3j)

=(12i-12j)

Magnitude=√(12i)^2 + (12j)^2

=√2×12×12

=12√2 J

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