Question

A force 40N inclined an angle 30 with horizontal. what are X and Y component of force?

Answer 1

GIVEN: Fx = 50 N ; θ = 30° ; Fy = ?

Fx = F Cosθ wherein θ = 30°

50 = F×√3/2

F = 50×2/√3

= 100/√3

= 57.73 N

Fy = F Sinθ

= 57.73×1/2

= 28.86 N.

Therefore, the magnitude of force = 57.73 N and the vertical component = 28.86 N.

Answer 2

Y component would be

40 sin 60

X component would be

40 cos30

Explanation: