a force 5N acting on a body at an angle of 30° with the horizontal direction displaces it horizontally through a distance of 6m. Calculate the work done..??
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Answered by
8
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work done=fscosФ
w=5*6*cos30deg
w=30*√3/2 [bcoz cos30 =√3/2]
w=15√3
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ayushmaan97:
bro tnx but something mistake ur ans is 15j but in real ans is15√3....but well done
yes m sry
no problem bro
but good
cos60=root3/2
it thought its cos60....sryy broo
i thought
np
bye
byee
Answered by
9
it should be the required answer
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tnx bro
your welcome ayushmann
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