Question

.
A force 7 = (6-87), acts on a particle and displaces it over 4 m along the X-axis
and then displaces it over 6 m along the Y-axis. The total work done during the
two displacements is
1) 72J
2) 24 J
3) - 24 J
4) zero​

Answer 1

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Answer 2

Answer:

w=(6×4)+(−6×6)

=24−48

=−24J

Explanation:

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