Question

A force act f equal to 5i+4j n on a body produced displacement s 6i-5j+3k the work done will be

Answer 1

F=5i+4j N
Displacement = 6i+5j+3k m

Since..- W. D. =F. d

W. D. = (5i+4j)•(6i+5j+3k)

W. D. =30i+20j joule.


Here displacement of z-axis is not considered bcz in z-axis no force is present.

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Answer 2

The work done by the body is 10 Joules.

Explanation:

Given that,

Force acting on a body, $F=(5i+4j)\ N$

Displacement in the body, $d=(6i-5j+3k)\ m$

To find,

Work done by the body.

Solution,

The work done by a body is given by the dot product of force and displacement. It is given by :

$W=F{\cdot} d$

$W=(5i+4j){\cdot} (6i-5j+3k)$

$W=30-20+0$

W = 10 Joules

So, the work done by the body is 10 Joules.

Learn more,

Work done

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