Question

A force act on stone of mass 200g the velocity of the stone change from15 meter per second to 25 meter per second in 2.5 second find the magnitude of force​

Answer 1

Answer:

given

mass of stone m = 200g=>0.2kg

initial velocity u=15ms^-1

final velocity v=25ms^-1

time t=2.5sec

net force f=?

w.k.t

F=ma

and

a=v-u/t

a=20-15/2.5

=2

therefore

F=0.2×2

=0.4

magnitude of force = 0.4newton