Physics, asked by ravinderrana5856, 1 year ago

A force acting gor 10s on the bady of mass 10kg after which the force ceases and the body describes 50m in next 5s what is the magnitude of force?

Answers

Answered by b394184
7
Well velocity of body is 50/5 = 10 m/s

initial velocity (u) = 0
Final velocity (v)= 10 m/s
Time taken (t)= 10 s

using a = (v-u)/t
a= 1 m/s^2

F = ma
F = 10 * 1
F = 10 Newtons.
Hope that helps
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