Question

a force acting on 2o kg mass change its velocity from 5 m/s to 2 m/s . calculate the work done​

Answer 1

Given,

Mass, m = 20 kg

Inital velocity, u = 5 m/s

Final velocity, v = 2 m/s

K.E = 1/2 m (v² - u²) = 1/2 × 20 × (2² - 5²) = –210J

Here, the nagative implies the retarding of the applied force.