a force acting on a 20 kg mass change its velocity from 5 m per second 2metre per second calculate the work done by the force
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2
F=ma
a=v/t-u/t
a=2-5
a=-3
m=20kg
D=-60N
a=v/t-u/t
a=2-5
a=-3
m=20kg
D=-60N
Answered by
2
Work done = Kinetic energy possessed by the mass
final velocity(v) = 5 m/s
initial velocity(u) = 2m/s
mass(m) = 20 kg
=1/2 m (v* - u*).
=1/2 x 20 x [(5)*-(2)*]
=1/2 x 20 x [25-4]
=1/2 x 20 x 21
=10 x 21
=210 Joule(J)
Please note that * is used in place of whole square
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