A force acting on a body changes its velocity from 10 ms^-1 to 15 ms^-1 with in a distance of 50 m. calculate the magnitude of force. mass of body is 10 kg.
Answers
Answered by
4
given:
initial velocity(u)= 10m/s
final velocity(v)=15m/s
distance (s)=50m
mass(m)=10kg
acceleration=?
force=?
v^2-u^2=2as(third eq.of motion)
15^2-10^2=2×a×50
225-100=100a
a=125÷100
a=1.25
force =mass×acceleration
=10×1.25
=12.5N
initial velocity(u)= 10m/s
final velocity(v)=15m/s
distance (s)=50m
mass(m)=10kg
acceleration=?
force=?
v^2-u^2=2as(third eq.of motion)
15^2-10^2=2×a×50
225-100=100a
a=125÷100
a=1.25
force =mass×acceleration
=10×1.25
=12.5N
Similar questions