a force acting on a body of mass 2 kg varies with time as shown in figure. find impulse of force and final velocity of force .
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6 ms^-1 .
Given:
- force acting on a body of mass 2 kg.
To Find:
- impulse of force and final velocity of force .
Solution:
Impulse = area under F-t graph
m ( υ − u ) = ( 4 × 2 / 2 ) + 4 × 1 + ( 4 × 2 ) / 2
= 12 N − s
2 ( υ − 0 ) = 12 ,
υ = 12 / 2
= 6
Thus the answer is 6 . [6 ms^-1]
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