Physics, asked by madipeddilatha, 7 months ago

A force acting on a body of mass 2kg increases its speed from 10m/s to 15m/s in 0.1 sec . the magnitude of force is ​

Answers

Answered by MяƖиνιѕιвʟє
42

Gɪᴠᴇɴ :-

  • Mass (m) = 2kg
  • Initial velocity (u) = 10m/s
  • Final velocity (v) = 15 m/s
  • Time taken (u) = 0.1 s

ᴛᴏ ғɪɴᴅ :-

  • Force (F)

sᴏʟᴜᴛɪᴏɴ :-

We know that,

Force(F) = Mass(m) × Acceleration(a)

F = ma

F = m × (v - u) /t

Put the above given values in it, we get,

F = 2 × (15 - 10)/0.1

F = 2 × 5/0.1

F = 2 × 50

F = 100 N

Hence,

  • Force (F) = 100 Newtons
Answered by MystícPhoeníx
64

_______________________________

✰ Question✰

⋄ A force acting on a body of mass 2kg increases its speed from 10m/s to 15m/s in 0.1 sec . the magnitude of force is

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❍ Given :-

⋄Mass of body (m) =2kg

⋄ initial velocity (u) =10m/s

⋄ Final velocity (v) =15m/s

⋄ Time taken (t) =0.1s

_______________________________

❍ To Find :-

⋄ Force acting on body.

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❍Solution :-

We know that,

Force is the product of mass and acceleration

➧ F=m× a

➧ F=2 × (v-u/t) ....... (a =v-u/t)

➧ F= 2× (15-10/0.1)

➧ F = 2×50

➧ F = 100N

∴The force acting on the body is 100N.

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