Question

A force acting on a conductor of length 5m carrying a current of 8 A kept perpendicular to the magnetic field of 1.5 T is
100N 60 N 50 N 75 N

Answer 1

Answer:

60 N

Explanation:

By the formula of Lorentz force,

F=BIL sin ø

B=1.5 T or 15/10 T

I=8A

L=5m

ø=90⁰

so,

F=(15/10)×8×5×sin90

F=(15/10)×40×1

F=15×4

F=60N