a force acting on a partical of mass 200g.the displaces it through 400cm in 2s. find the magnitude of the force if the initial velocity of the partical is zero.
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3
If the initial velocity of the particle is zero then acceleration is,
a = 2s/t^2
Here,
s=400 cm=4 m and t=2 s.
So we have,
a=2×4/2^2=2
Now,
mass m=200 g = 0.2 kg.
So force f=ma=0.2×2=0.4 N
a = 2s/t^2
Here,
s=400 cm=4 m and t=2 s.
So we have,
a=2×4/2^2=2
Now,
mass m=200 g = 0.2 kg.
So force f=ma=0.2×2=0.4 N
Answered by
1
first good question
now 200g =.2 kg
and 400cm=4m
time = 2s
f=mass * acceleration
now s=ur+1/2at square
now 4m=0*2+1/2a4
now 4m =0 +1/2a4
4m*2=0+1a4
8m=4a
a=2m/square
now f=.2*2
=.4N
plz mark it brainlist
now 200g =.2 kg
and 400cm=4m
time = 2s
f=mass * acceleration
now s=ur+1/2at square
now 4m=0*2+1/2a4
now 4m =0 +1/2a4
4m*2=0+1a4
8m=4a
a=2m/square
now f=.2*2
=.4N
plz mark it brainlist
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