Question

a force acting on a particle of a man 200 gm displaces it through 400cm in 2 second. find the magnitude of its force if initial velocity of particle is zero​

Answer 1

Explanation:

Given:

mass=m=200g=0.2kg

distance =s=400cm=4cm

time =t=2sec

u=0m/s

find f??

find f??By second law of motion,

S=ut+1/2at^2

=> 0+1/2×a×4=4

=> a=2m/s^2

By second equation of motion,

F=ma

=> 0.2×2=0.4N

Therefore, Magnitude of force is 0.2N..........

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