Question

A force acting on a particle of mass 200g displaces it through 400 cm in 2s. if the initial velocity of the particle is zero, then the magnitude of the force is?​

Answer 1

Answer:

given that:

m=200g or 0.2kg ,t=2s ,d=4m and F=?,a=?

F=ma

s=1/2ut+at^2

s=at^2{as u is 0}

4m=a×(2s)^2

4m=a×4s^2

4m/4s^2=a

So,a=1m/1s^2

Now,F=ma

F=0.2kg×1m/1s^2

So,F=0.2Newtons

Explanation:

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Answer 2

Answer

Magnitude of the force = 0.4 N

Given

A force acting on a particle of mass 200 g displaces it through 400 cm in

2 s

To Find

If the initial velocity of the particle is zero, then the magnitude of the force is

Formula Applied

2nd equation of motion

$\to \rm s=ut+\dfrac{1}{2}at^2$

Newton's Second Law

$\to \rm F=ma$

Solution

Mass , m = 200 g = 0.2 Kg

Displacement , s = 400 cm = 4 m

Time , t = 2 s

Initial velocity , u = 0 m/s

Apply 2nd equation of motion ,

$\to \rm s=ut+\dfrac{1}{2}at^2\\\\\to \rm 4=(0)(2)+\dfrac{1}{2}a(2)^2\\\\\to \rm 4=0+2a\\\\\to \rm a=2\ m/s^2$

Apply Newton's Second Law ,

$\to \rm F=ma\\\\\to \rm F=(0.2)(2)\\\\\to \rm F=0.4\ N$

So , Magnitude of the force = 0.4 N