A force acting on a particle of mass 200g. The velocity of particle changes from 15m/'s to 25m/sec in 2s.find it's magnitude
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given:u=15m/s
v=25m/s
t=2s
m=200g
hence, f=m*a
a=(v-u),/t
f=m*(v-u) /t
f=200g*(25-15)/2
f=0.2kg*10/2
f=0.2*5kgm/s^2
f=1kgm/s^2
f=1N
so, the magnitude is of 1 N
v=25m/s
t=2s
m=200g
hence, f=m*a
a=(v-u),/t
f=m*(v-u) /t
f=200g*(25-15)/2
f=0.2kg*10/2
f=0.2*5kgm/s^2
f=1kgm/s^2
f=1N
so, the magnitude is of 1 N
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