Question

A force acting on a particle of mass 200g. The velocity of particle changes from 15m/'s to 25m/sec in 2.5s.find it's magnitude

Answer 1

Answer:

Explanation:

Given u = 15 m/s and v = 25 m/s, mass = 200g=0.2 kg and time t = 2.5 s.

We have v = u + at

a = (v - u)/t

a = (25 - 15)/2.5

a = 10/2.5 = 100/25 = 4 m/s2  

Therefor F = ma = 0.2 x 4 =0.8 N