A force acting on a particql of mass 200g. the velocity of particals changes fraom 15m/s to 25m/s in 2.5 sec. find the magnitude of force
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Final Answer : 0.8N
Steps and Understanding :
1) By Newtons Second Law of Motion,
Force is rate of change of Momentum,
Here, assuming Force is constant.
Mass of particle, m = 200g = 0.2Kg
Final Velocity, v = 25m/s
Initial Velocity, u = 15m/s
Time taken, t = 2.5s
Then,
F = m(v-u) /t
= 0.2 (25-15)/2.5
=0.8N
Magnitude of Force is 0.8N .
Steps and Understanding :
1) By Newtons Second Law of Motion,
Force is rate of change of Momentum,
Here, assuming Force is constant.
Mass of particle, m = 200g = 0.2Kg
Final Velocity, v = 25m/s
Initial Velocity, u = 15m/s
Time taken, t = 2.5s
Then,
F = m(v-u) /t
= 0.2 (25-15)/2.5
=0.8N
Magnitude of Force is 0.8N .
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