Question

A force action on a 32 particle in such a way that the position of the particle as a function of time is given by
x = 3t − 4t^2 + t^3
where x is in metre and t is in second. The workdone during the first 4s is

(A) 570 mJ (B) 450 mJ
(C) 490 J (D) 528 J

Answer 1

Answer:

question is not clear some thing is missing