Question

a force action on an object of mass 10kg raises its speed from 2ms^-1 to 5ms^-1 in 10 sec find the acceleration and magnitude of force​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Force=3\:N}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Mass \: of \: body(m) = 10 \: kg \\ \\ \tt: \implies Initial \: speed(u) = 2 \: m/s \\ \\ \tt: \implies Final \: speed(v) = 5 \: m/s \\ \\ \tt: \implies Time (t) = 10 \: sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Force \: Applied(F) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 5 = 2 + a \times 10 \\ \\ \tt: \implies 5 - 2 = 10 \times a \\ \\ \tt: \implies a = \frac{3}{10} \\ \\ \tt: \implies a = 0.3 { \: m/s}^{2} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies F = ma \\ \\ \tt: \implies F = 10 \times 0.3 \\ \\ \green{\tt: \implies F= 3 \: N} \\ \\ \green{\tt \therefore Force \: applied \: on \: object \: is \: 3 \: N}$

Answer 2

Aɴsᴡᴇʀ :

➥ The force applied of an object = 3 N

Gɪᴠᴇɴ :

➤ Mass of an object (m) = 10 kg

➤ Intial velocity of an object (u) = 2 m/s

➤ Final velocity of an object (v) = 5 m/s

➤ Time taken (t) = 10 sec

Tᴏ Fɪɴᴅ :

➤ Force applied of an object (F) = ?

Sᴏʟᴜᴛɪᴏɴ :

From first equation of motion

$\sf{:\implies v = u + at}$

$\sf{:\implies 5 = 2 + a \times 10}$

$\sf{:\implies 5 -2 = 10 \times a}$

$\sf{:\implies a = \cancel{\dfrac{3}{10}}}$

$:\implies\purple{\underline{\overline{\boxed{\green{\bf{\:\: a = 0.3 \: m/s^2 \:\: }}}}}}$

Now,

$\sf{: \implies F = ma}$

$\sf{: \implies F = 10 \times 0.3}$

$\sf{: \implies \green{\underline{ \overline{ \boxed{ \purple{ \bf{ \: \: F = 3 \: N \: \: }}}}}}}$

Hence, the force applied of an object is 3 N.