A force acts for 0.1 s on a body of mass 2.0 kg
initially at rest. The force is then withdrawn and
the body moves with a velocity of 2 ms. Find the
magnitude of force.
Ans, 40 N
Answers
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Answer:
T=. 1s
M=2kg
V=2m/s
U=0
Explanation:
V=u+at
2m/s=o+a×0.1s
a=20m/s^2
F=ma
F=2kg×20m/s^2
F=40n
Foce motion ki darection mai lagega
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