Question

A force acts for 0.1s on a body of mass 2.0kg initially at rest. The force is withdrawn and the body moves with the velocity of 2m/s. Find the magnitude of force

Answer 1

So the answer will be 40N

Answer 2

40N

Explanation :

u=0

v=2ms-1

t=0.1s

m= 2.0kg

f=?

A= final velocity- initial velocity/time taken

a =v-u\t

a=2-0\0.1 =20\0.1 = 20ms

F =m×a

f = 2.0×20

f = 40N ANS