Question

a force acts for 0.1s on a body of mass 2kg initially at rest.the force is then withdrawn and the body moves with a velocity 2m/s .find the magnitude of force

Answer 1

F = m(v - u)/t
u = 0
F = mv/t
F = 2 * 2 / 0.1
F = 40 N

Magnitude of Force is 40N

Answer 2

hope it helps .......