a force acts for 0.2 sec on an object having a mass 1.4 initially at rest .the force stops to act but the object moves through 4m in the next 2sec find the magnitude of the force
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F = mv/t
v = Ft/m
= F * 0.2 / 1.4
= F/7
v = u + at
0 = F/7 + 2a
a = -F/14
S = v^2 - u^2 / (2a)
4 = (0 - F^2/49) / (2*(-F/14))
-4 * 2 * F/14 = - F^2 / 49
4F/7 = F^2 / 49
F = 4 * 49/7
F = 28 N
Magnitude of Force is 28 N
v = Ft/m
= F * 0.2 / 1.4
= F/7
v = u + at
0 = F/7 + 2a
a = -F/14
S = v^2 - u^2 / (2a)
4 = (0 - F^2/49) / (2*(-F/14))
-4 * 2 * F/14 = - F^2 / 49
4F/7 = F^2 / 49
F = 4 * 49/7
F = 28 N
Magnitude of Force is 28 N
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