Question

A force acts for 0.2 sec on an object having mass 1.4 kg initially at rest.the force stops to act but objects moves through 4m in the text 2 seconds find the magnitude of the force

Answer 1

Initial velocity(u)=0

Final velocity(v)=?

Time Object moves after force stops(t)=2 s

Distance(s)=4 m

v=s/t

v=4/2=2 m/s

Time force acts on object(t')=0.2 s

Mass(m)=1.4 kg

Acceleration(a)=?

v=u+at

2=0+a×0.2

2/0.2=a

10 m/s²=a

F=ma

F=1.4×10

F=14 Newton

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Answer 2

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Time=0.2sec.

Mass=1.4kg.

After force stops object moves through 4m in next 2sec.

Distance=4m.

Time=2m/s.

v=distance/ time.

v=4/2

velocity=2m/s.

Initial velocity(u)=0.

final velocity(v)=2.

a=v-u/t.

Acceleration=10m/s.

Force= mass* acceleration.

Force=1.4*10.

Force=14N.

Magnitude of the force=14N..

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