Question

A force acts for 0.2sec on an object having mass 1.4kg initially at rest.The force stops to act but the object moves through 4m in next 2 sec find the magnitude of the force?

Answer 1

After the force has stopped acting, the object will move with constant velocity. This velocity can be found as
V = D/T
V = 4/2 = 2m/s
Now we know the final velocity of the object.
Initially the object is at rest, meaning its initial velocity is 0 or zero.
Hence we can find the acceleration
A = (V-U)/T
A = (2 - 0)/0.2
A = 10 m/s^2
Now since we have acceleration and mass we can find force.
F = M×A
F = 1.4 × 10
F = 14 N

Hence the magnitude of the force is
14 Newton

Answer 2

heya...

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