Question

A force acts for 1 second on a body of 12 kg. The force is withdrawn. The body then moves to a distance
of 2 m in the next second. Find the magnitude of force.
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Answer 1

Answer:

The magnitude of force is 48N.

Explanation:

Let the force be F.

mass of body= 12kg

F=ma

=> a= F/m= F/12

Distance travelled, S= 2m

time= 1sec

initial speed, u=0

S= ut+1/2a(t)^2

S= 0+1/2×[F/12]×(1)^2

F/24= 2

F= 48N

HOPE, it helps!