Question

A force acts for 10 s on a body of mass 10 kg after
which the force ceases and the body describes 50 m
in the next 5 s. Find the magnitude of the force.
​

Answer 1

Answer:

After 10s ,the force ceases and the body starts moving with velocity v.It covers 50m in 5s. s=vt=50m. a=1m/s^2. F=10*1N.

Answer 2

Answer:

Let the body starts from rest.

∴u=0

Final velocity = distance / time = 50/5 = 10 m/s

Now, using equation of motion, v = u + at

a=

t

v−u

=

10

10−0

=1ms

−2

Force = F= ma = 10kg×1ms

−2

= 10 N