A force acts for 10 s on a stationary body of mass
100 kg after which the force ceases to act. The body
moves through a distance of 100 m in the next 5 s.
Calculate : (i) the velocity acquired by the body,
(ii) the acceleration produced by the force, and (iii)
the magnitude of the force.
Answers
Answer:
velocity = displacement into time
acceleration = force divided by mass
a= 1a 1b 1c
Explanation:
my explanation vis just I'm telling you formula you can solve this if you are facing any problems first without fear just ask to you teacher ok
Answer:
20m/s,2m/s^2 and 200N
Explanation:
Mass, m=100kg
Time interval, t=10s
(i) Distance traveled in next 5 seconds, d=100m
Thus, velocity acquired by body, v = d/t
= 100/5
=20m/s
(ii)Acceleration produced by the force, a= v/ t
= 20/10
=2m/s^2
(iii) Magnitude of force, F=ma
=100kg∗2m/s^2
=200N