Physics, asked by rajarshikamalabas, 10 months ago

A force acts for 10 s on a stationary body of mass
100 kg after which the force ceases to act. The body
moves through a distance of 100 m in the next 5 s.
Calculate : (i) the velocity acquired by the body,
(ii) the acceleration produced by the force, and (iii)
the magnitude of the force.​

Answers

Answered by bk215263
2

Answer:

velocity = displacement into time

acceleration = force divided by mass

a= 1a 1b 1c

Explanation:

my explanation vis just I'm telling you formula you can solve this if you are facing any problems first without fear just ask to you teacher ok

Answered by aanyaagarwal7002
5

Answer:

20m/s,2m/s^2 and 200N

Explanation:

Mass, m=100kg

Time interval, t=10s

(i) Distance traveled in next 5 seconds, d=100m

Thus, velocity acquired by body, v = d/t

​                                                            = 100/5

                                                          =20m/s

(ii)Acceleration produced by the force, a= v/ t

                                                                   =  20/10

​                                                                    =2m/s^2

 

(iii) Magnitude of force, F=ma

                                         =100kg∗2m/s^2

                                         =200N

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