A force acts for 10 seconds on a body of mass 10^-2kg, initially at rest . After which it force ceases to act . After this body moves for 0.5 m in 5 seconds.
Calculate the force
Answers
Say initial velocity is 0
then, v=u+at
v= 0+ a10
v=10a
After 10s body starts moving and cover 100m in 5s
S= vt
100= (10a) 5
a=2m/s2
using the value of a in F=ma
F=100x2=200N
and v=10a =10 x 2= 20m/s
:) Cheers
2.2k Views ·
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A force acts on a stationary body for 10 s and stops. After the force stops to act on the body, it covers a distance of 100 m in 5 s. We are required to find the (uniform) acceleration on the body due to force.
To solve this problem, we need to remember that after a force stops to act, the body will move with uniform velocity ( ignoring friction). Since the body covers 100 m in 5 s, its velocity at the end of acceleration period is,
v = 100 m/ 5 s = 20 m/s.
This final velocity has happened due to the force producing acceleration on the stationary body for 10 seconds. Using the relation,
v = u + a t ,
we have, u = 0 m/ s, v = 20 m/s, we get,
a = ( 20 m/s - 0 m/s) / 10 s = 2 m/s².
So the acceleration on the body is 2 m/s².
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Suppose acceleration is a. With this acceleration the velocity of the body is u=at=10a after 10s.
For the next part of motion, we use distance
d=ut’+(1/2)at’^2=50a+(1/2)a(25)=50a+12.5a=62.5a. Here, we assume that force continues to act. The next time interval has been t’=5s. Now, taking d=100 m, we get,
100=62.5a or
a=100/62.5m/s^2
463 Views · Answer requested by
Since it starts from rest final velocity v = at = 10a and final velocity = distance / time = 100/5 = 20 m/s.
a = 20/10 = 2 m/s^2 .
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u = 0 m/s
s = 100 m
t = 10 s
m = 100 kg
APPLE 2nd EQ OF MOTION.
s = ut + ½ at²
100 = 0×10 + ½ × a × (10)²
a = 100/50 = 2 m/so
a = 2 m/s²
Mass of the body = 10 kg
Initial velocity u = 4 m/s
Final velocity v = 8 m/s
Time t = 2 s
(a) Momentum before force acts p1 = m x u = 10 x 4 = 40 kg.m/s
(b) Momentum after force acts p2 = m x v = 10 x 8 = 80 kg.m/s
(c) Gain in momentum for 2 s = p2 -p1 =40 kg.m/s
Gain in momentum per second = 40/2 = 20 kg.m/s