Question

a force acts for 10 seconds on a stationary body of mass 100 kg after which the force ceases to act.The body moves through a distance of 100m in the next 5s.Calculate:the velocity acquired by the body,the acceleration produced by the force and the magnitude of the force.​

Answer 1

Answer:

The velocity acquired by the body is 40 m/s, the acceleration produced by the force is 8 m/s squared and the magnitude of Force is 800 Newtons.

Explanation:

$t=5sec$

$m=100kg$

$s=100m$

$u=0m/s$(As it is starting to move from rest)

$a=?$

$v=?$

$F=?$

Second Equation of Motion:

$s=ut+\frac{1}{2}a{t}^2$

$100=(0*5)+\frac{25a}{2}$

$25a=2*100$

$25a=200$

$a=\frac{200}{25}$

$a=8m/{s}^2$

First Equation of Motion:

$v=u+at$

$v=(0)+(8*5)$

$v=40m/s$

From Sir Isaac Newton's Second Law of Motion we know that:

$F=ma$

$F=100*8$

$F=800N$

Answer 2

Answer:

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Explanation:

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