a force acts for 10 seconds on a stationary body of mass 100 kilogram after was the first ceases to act . The body moves a distance of 100 metre in the next 5s calculate: (i) the velocity acquired by the body (ii) The acceleration produced by the force (iii) magnitude of the force
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Step-by-step explanation:
Let initial velocity = u = 0
Using equation of motion, v = u +at = 0+a(10) = 10a
distance in 10 sec = s = vt = 100=10a(5)
a=2m/s2
∴v=10a=10(2)m/s=20m/s
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