A force acts for 10s on a body of mass 10 kg after which the force ceases and the body describes 50 m in the next 5 s. Find the magnitude of the force.
Answers
Answered by
11
Answer:
m=10kg.
F=ma.
Using v-u=at.
t=10s.
v=at.(considering the body starts from rest).
After 10s ,the force ceases and the body starts moving with velocity v.It covers 50m in 5s.
s=vt=50m.
s=(10a)5=50
a=1m/s^2.
F=10*1N.
F=10N.
pls mark brainliest
Similar questions