Question

A force acts for 10s on a body of mass 10 kg after which the force ceases and the body describes 50 m in the next 5 s. Find the magnitude of the force.​

Answer 1

Answer:

m=10kg.

F=ma.

Using v-u=at.

t=10s.

v=at.(considering the body starts from rest).

After 10s ,the force ceases and the body starts moving with velocity v.It covers 50m in 5s.

s=vt=50m.

s=(10a)5=50

a=1m/s^2.

F=10*1N.

F=10N.

pls mark brainliest