A force acts for 10s on a stationary body of mass 100kg after which the force ceases to act. The body moves through a distance of 100m in the next 5s. Calculate: (i) the velocity acquired by the body, (ii) the acceleration produced by the force, and (iii) the magnitude of the force. ty
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Answer:
Explanation:
Mass, m= 100kg
Time interval, At = 10s
(i) Distance traveled in next 5 seconds, d= 100m
Thus, velocity acquired by body, v = d/t 100/5 = 20m/s
(ii) Acceleration produced by the force, a = V/T= 20/10= 2m/s²
(iii) Magnitude of force, F=ma 100kg + 2m/s² = 200N
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