Question

A force acts for 10sec on a body of mass 10kg after which the force ceases and the body describes 50m in the next 5sec. find the magnitude of the force​

Answer 1

Answer:

Accn. To qstn

F=10.a so,

a=F/10

Now qfter 10s final velocity, V=0+F/10.10.

So, V=F........

Now.. From 2nd eq of motion

S=ut+1/2at2

50=F.5+1/2.F/10.25

On solving it we get

F=8N.