Question

A force acts for 10sec on a body of mass 10kg after which the force ceases and the body describes 50m in the next 5 sec .find the magnitude of the force

Answer 1

ANSWER:
m=10kg.
F=ma.
Using v-u=at.
t=10s.
v=at.(considering the body starts from rest).
After 10s ,the force ceases and the body starts moving with velocity v.It covers 50m in 5s.
s=vt=50m.
s=(10a)5=50
a=1m/s^2.
F=10*1N.
F=10N.

Answer 2

Refer to the attachment for your answer.......