A force acts for 2 seconds on a body of mass 2 kg initially at rest. Just after the force stops to act the body moves 1O m in the next 2 seconds. Find the magnitude of the force. Show full steps to solve.
Answers
Answer:
THE MAGNITUDE OF FORCE IS 10N
Explanation:
GIVEN,
Time(t)=2 seconds
Displacement(s)=10m
Mass(m)=2kg
Initial velocity(u)=0m/s
TO FIND,
The magnitude of force(f)
SOLUTION ,
s=ut+1/2+at²
10=0×2+1/2×a×(2)²
10=1/2×a×4
10=2a
10/2=a
a=5m/s²
F=ma
F=2×5
F=10N
HOPE ITS HELPFUL GUYS,
THANK YOU FOR READING MY SOLUTION
Given: A force acts for 2 seconds on a body of mass 2 kg initially at rest. Just after the force stops to act the body moves 10 m in the next 2 seconds.
To find: Magnitude of the force
Explanation: When the force stops to act, the body moves with constant velocity without any acceleration.
Velocity= Displacement/ Time
= 10 m/ 2 s
= 5 m/s
This means that the force starts the body from rest and stops acting when it reaches the velocity of 5 m/s.
For this motion, Final velocity (v)= 5 m/s
Initial velocity (u) = 0
Time (t)= 2 seconds
Acceleration provided by the force
=v-u/t
= 5-0/2
= 2.5 m/s^2
Mass of the body= 2 kg
Force on the body for first 2 second
= Mass * Acceleration
= 2 * 2.5 N
= 5 N
Therefore, the magnitude of the force is 5 N.