Question

A force acts for 2 seconds on a body of mass 2 kg initially at rest. Just after the force
stops to act the body moves 10 m in the next 2 seconds. Find the magnitude of the force.​

Answer 1

Total time=2sec

Mass=2kg

Initial velocity (u)=0m/s

Final velocity (v)=Distance/Time

=10/2

=5m/s

Acceleration(a)=v-u/t

=5-0/2

=5/2m/s²

Force (F)=ma

=2×5/2

=5N (Ans)

Please mark it as a brainliest answer.

Answer 2

Given:

✰ Time ( t ) = 2 s

✰ Mass ( m ) = 2 kg

✰ Initial velocity ( u ) = 0 m/s

✰ Displacement ( S ) = 10 m

To find:

✠ The magnitude of the force ( F ).

Solution:

Using 3rd equation of motion,

S = ut + 1/2 at²

➯ 10 = 0 × 2 + 1/2 × a × (2)²

➯ 10 = 0 × 2 + 1/2 × a × 4

➯ 10 = 1/2 × a × 4

Now, 2 gets cancel with 4

➯ 10 = 1 × a × 2

➯ 10 = 2a

➯ a = 10/2

➯ a = 5 m/s²

Now, we know that force is the product of mass and acceleration.

F = ma

➯ F = 2 × 5

➯ F = 10 N

∴ The magnitude of the force ( F ) = 10 N

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