A force acts for 2 seconds on a body of mass 3 kg initially at rest. The force then ceases to act and the body moves through 5 m in the next one second. Find magnitude of force.
Answers
Answer :-
Magnitude of force is 7.5 Newtons .
Explanation :-
We have :-
→ Initial velocity (u) = 0 m/s
→ Mass of the body (m) = 3 kg
→ Time for action of force (t) = 2 sec
→ Distance (after force ceases) = 5 m
→ Time (after force ceases) = 1 sec
______________________________
From the question, we can understand that a force acts on a body for 2 seconds. After the force ceases, the body moves with constant speed (as there is no acceleration) for 1 second.
So, speed of the body after action of force :-
⇒ Speed = Distance/Time
⇒ v = 5/1
⇒ v = 5 m/s
______________________________
Now, we will calculate the acceleration of the body for the time when force was acting .
v = u + at
⇒ 5 = 0 + a(2)
⇒ 5 = 2a
⇒ a = 5/2
⇒ a = 2.5 m/s²
Finally, we can calculate the magnitude of force by putting obtained values in Newton's 2nd law of motion .
F = ma
⇒ F = 3 × 2.5
⇒ F = 7.5 N
Explanation:
given :
- a force = 0 m/s
- body of mass = 3 kg
- force action that body move = 2 sec
- force then ceases = 5m
- magnitude of force = 1 sec
to find :
- Find magnitude of force.
solution :
- please check the attached file
learn more:
- the formula is V = u + at
- in this question we calculate the acceleration
- and the we also calculate the magnitude
- then , we have also find body action force
