Physics, asked by raunancMIN, 1 year ago

A force acts for 20 sec on a body of mass 10 kg after which the force ceases and the body describes 50m in next 10 sec.Find the magnitude of the force?

Answers

Answered by devdonawithrrt

1

v=50/1
v=5m/s
F*t=m*dv
F=m*dv/t
F=10*5/20
F=2.5Newton

Previous Question

Next Question

Similar questions

English, 9 months ago

Short story on slow and steady wins the race...

English, 9 months ago

How did anne pay tribute to her grandmother...

History, 9 months ago

struggle What were the qualifications necessary to become a member of a committee of the sabha in the Chola empire?

English, 1 year ago

Poem on role of women in india's freedom movement...

English, 1 year ago

Poem on unique feature of indias freedom movement...

Physics, 1 year ago

The refractive index of glass is 1.50 and speed of light in air is 3×100000000. Calculate the speed of light in glass...

English, 1 year ago

homeworks are burden...

English, 1 year ago

your brother is a part of a school hockey team and is it's best player his friend is also a part of team but he trys to keep your brother out of practice session and tournament your brother is a hurt but does not want to offend his friend what could you do help your brother? what step you would suggest to help to resolve the issue...