Question

a force acts for 20 seconds on a body of mass 5 kg and then ceases to act the body moves uniformly and describes 10 metre in the next 5 second find the magnitude of the force.​

Answer 1

Answer:

Explanation:

Let the body starts from rest

so, u=0

Final velocity = distance/time = 10/5 = 2m/s

Now using equation of motion, v=u+at

a = v-u/t = 2-0/20 = 0.1ms^-2

Force = F = ma = 5*1/10 = 1/2N = 0.5N