Question

A force acts for 3 s on a stationary body of mass 90 g after which the force
ceases to act. The body moves through a distance of 80 m in the next 5 s.
Calculate the magnitude of the force.​

Answer 1

Answer:

Let initial velocity = u = 0

Using equation of motion, v = u +at = 0+a(10) = 10a

distance in 10 sec = s = vt = 100=10a(5)

a=2m/s

2

∴v=10a=10(2)m/s=20m/s