Question

A force acts for 5 seconds on a mass of 20 kg and then ceases to act. During the next 5 second the
body covers 150 m. Find the magnitude of force, if the body was initially at rest.​

Answer 1

Explanation:

Using second equation of motion we can find the acceleration

⇒s=ut+

2

1

at

2

⇒5=0(5)+

2

1

a5

2

⇒a=

5

2

m/s

2

And hence, F=ma=

5

2

×10=4N