Question

a force acts for 5s on a body of mass 2 kg initially at rest. the force is then withdrawn and the moves with a velocity of 2ms-1. find the magnitude of force​

Answer 1

Answer:

Mass, m=2kg

Initial velocity, u=0

Final velocity, v=2m/s

Change in velocity, Δv=v−u=2m/s

Time interval, Δt=0.1s

Acceleration, a=

Δt

Δv

=

0.1

2

=20m/s

2

Force, F=ma=2kg×20m/s

2

=40N