Question

a force acts in a 16 gm mass for 3 sec and then force is withdrawn.in the next 3 sec the body travelled 81 cm.what force is acting on the body ?​

Answer 1

Mass = 16 kg

Time(t) = 3sec

Distance traveled = 81m

→

Final velocity (V) of body = D/t

=> 81/3

=> 27 m/s

Now,

We know

V = u + at

27 = 0 + a × 3 {Initial velocity (u) = 0}

a = 9 m/s²

Force(F) = Mass (m) × Acceleration (a)

=> 16 × 9

=> 144 N

Answer 2

Answer:

i entered to class 8 I don't know the answer,sorry