Question

a force acts on 3g particle in such a way that the position of the particle as a function of times is given by x=3t-4t^+ t power 3 where x is in meter and t is in seconds .the work done during first 4 sec is

Answer 1

  first   let us find the a of particle 

                           after double differenciating the equation we get a = -8+4t    ;  put t=4 to get a = 8 

                       now in the given eq.  subsitute t=4 to get the displacement as 12

                                   w=f.d          thus w = 3/1000 * 8*12 =0.288