A force acts on a 3 g particle in such a way that position of particle as a function of time is given
x = 3t - 4t2 + t3,where x is in metre and t is in sec. The work done during first 4sec is
(1) 570 mJ
(2) 450 mJ
(3) 490 mJ
(4) 528 mJ
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Answer (4)528mJ
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